**Definite vs Indefinite integral**

**Example**

**Some properties of definite integrals**

This website is dedicated to students taking additional mathematics (or A Maths in short) for O levels or N levels. Notes, worked examples, and questions are provided here. I hope that through the use of these educational resources, you will be able to study for your examinations quickly and effectively. Good luck for your examinations!

Integration is the reverse of differentiation.

If you differentiate A and get B --> Means if you integrate B you get back A!

The gradient at the maximum and minimum point is 0. Thus, to find maximum and minimum, these are the steps required.

Step 1: If you need to find maximum or minimum value of V, you first need an equation involving V.

Step 2: Differentiate the equation, to find e.g. dV/dx.

Step 3: Equate dV/dx to 0, and find x.

Step 4: Substitute x into equation of V (from step 1) to find the stationary value of V.

Step 5: To determine maximum or minimum, differentiate dV/dx to find dIf d

If d^{2}V/dx^{2 }< 0, V is maximum.

It refers to the change of a physical quantity with time. One good example is speed.

Speed is the change in distance per unit time. If we let distance be *s*, and let time be *t*. In Mathematical terms, the rate of change of *s* with respect to *t* can be written as:

What is the units of *ds/dt*? Since distance, *s,* has a unit of metre, and time, *t*, has a unit of seconds, then *ds/dt* has units of *m/s*.

If you know the rate of change of *x* with time (*dx/dt*),and need to find the rate of change of *V* with time (dV/dt), you need an equation with *V* and *x*, and subsequently differentiate it to find *dV/dx*. Using the following equation, *dV/dt* can be found.

A tangent is a line that touches the curve.

A normal is a line that is perpendicular to the normal.

Remember this formula:

(gradient of tangent) x (gradient of normal) = -1

How to find gradient of tangent at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent.

How to find gradient of normal at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent.

3) find gradient of normal by using the following formulae: -1 / (gradient of tangent)

How to find equation of tangent at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent. Let's call it m1.

3) substitute x into the y equation, to get a y value. Let's call this y value y1.

4) equation of equation : y -y1 = m1(x-a)

A normal is a line that is perpendicular to the normal.

Remember this formula:

(gradient of tangent) x (gradient of normal) = -1

How to find gradient of tangent at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent.

How to find gradient of normal at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent.

3) find gradient of normal by using the following formulae: -1 / (gradient of tangent)

How to find equation of tangent at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent. Let's call it m1.

3) substitute x into the y equation, to get a y value. Let's call this y value y1.

4) equation of equation : y -y1 = m1(x-a)

How to find equation of tangent at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent. Let's call it m1.

3) substitute x into the y equation, to get a y value. Let's call this y value y1.

4) equation of equation : y -y1 = m1(x-a)

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent. Let's call it m1.

3) substitute x into the y equation, to get a y value. Let's call this y value y1.

4) equation of equation : y -y1 = m1(x-a)

How to find equation of normal at x = a?

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent. Let's call it m1.

3) Find gradient of normal by using the formula gradient of normal = -1/ (gradient of tangent).

Let's call this gradient of normal m2.

3) substitute x into the y equation, to get a y value. Let's call this y value y1.

4) equation of equation : y -y1 = m2(x-a)

1) Differentiate y (find dy/dx)

2) substitute x = a into dy/dx to find gradient of tangent. Let's call it m1.

3) Find gradient of normal by using the formula gradient of normal = -1/ (gradient of tangent).

Let's call this gradient of normal m2.

3) substitute x into the y equation, to get a y value. Let's call this y value y1.

4) equation of equation : y -y1 = m2(x-a)

Differentiation formulae for algebraic, trigonometry, exponential, and logarithm:

Note:

*f(x) and g(x) are functions.*

*f'(x) means differentiation of f(x).*

*g'(x) means differentiation of g(x).*

Note:

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